TypeError: Circle() takes 1 positional argument but 2 were given in Python 3.10.12 shapes implementation

I'm working on a shapes implementation in Python 3.10.12 and encountering a TypeError when trying to create a Circle object. Here's the relevant code:

Here is the code for shape.py

class Shape:    def __init__(self, name):        self.name = name    def perimeter(self):        raise NotImplementedError("perimeter")    def area(self):        raise NotImplementedError("area")class Square(Shape):    def __init__(self, name, side):        super().__init__(name)        self.side = side    def perimeter(self):        return 4 * self.side    def area(self):        return self.side**2class Circle(Shape):    def __init__(self, name, radius):        super().__init__(name)        self.radius = radius    def perimeter(self):        return 2 * math.pi * self.radius    def area(self):        return math.pi * self.radius**2

Here is the code for test.py

from shape import *examples = [Square("sq", 3), Circle("ci", 2)]  # Error occurs herefor thing in examples:    n = thing.name    p = thing.perimeter()    a = thing.area()    print(f"{n} has perimeter {p} and area {a}")

The error message states:

TypeError: Circle() takes 1 positional argument but 2 were given

It states that erroe is in line 3 of test.py

Additional Information:

1. Course: Learning Software Design by Example (third-bit)
2. Problem link: https://third-bit.com/sdxpy/oop/: https://third-bit.com/sdxpy/oop/

Thank you in advance for your assistance!

dthedev@dip:~/python$ python3 test.pyTraceback (most recent call last):  File "/home/dthedev/python/test.py", line 3, in <module>    examples = [Square("sq", 3), Circle("ci", 2)]TypeError: Circle() takes 1 positional argument but 2 were givendthedev@dip:~/python$