So this is embarrassing. I've got an application that I threw together in Flask and for now it is just serving up a single static HTML page with some links to CSS and JS. And I can't find where in the documentation Flask describes returning static files. Yes, I could use render_template but I know the data is not templatized. I'd have thought send_file or url_for was the right thing, but I could not get those to work. In the meantime, I am opening the files, reading content, and rigging up a Response with appropriate mimetype:
import os.pathfrom flask import Flask, Responseapp = Flask(__name__)app.config.from_object(__name__)def root_dir(): # pragma: no cover return os.path.abspath(os.path.dirname(__file__))def get_file(filename): # pragma: no cover try: src = os.path.join(root_dir(), filename) # Figure out how flask returns static files # Tried: # - render_template # - send_file # This should not be so non-obvious return open(src).read() except IOError as exc: return str(exc)@app.route('/', methods=['GET'])def metrics(): # pragma: no cover content = get_file('jenkins_analytics.html') return Response(content, mimetype="text/html")@app.route('/', defaults={'path': ''})@app.route('/<path:path>')def get_resource(path): # pragma: no cover mimetypes = {".css": "text/css",".html": "text/html",".js": "application/javascript", } complete_path = os.path.join(root_dir(), path) ext = os.path.splitext(path)[1] mimetype = mimetypes.get(ext, "text/html") content = get_file(complete_path) return Response(content, mimetype=mimetype)if __name__ == '__main__': # pragma: no cover app.run(port=80)Someone want to give a code sample or url for this? I know this is going to be dead simple.