time limit exceed in the code that sums the numbers

in the question there will be a number taken from user. Up to that number, I want to find the sum of all numbers if the sum of that number's digits is odd.For example if the input is 13 then ;1+3+5+7+9+10+12 = 47 should be the result.In order to prevent time limit exceed, question says "Since the answer might be too big, please print the answer in modulo 10^9+7"

Constraints1 ≤ n < 10^17 (n is input)

Here is my code:

MOD = 1000000007def getSum(number):    total = 0    while number > 0:        total += number % 10        number //= 10    return (total % MOD) % 2def sticker(number):    stickerNeed = 0    for oneDigit in range(1, number):        if (getSum(oneDigit % MOD) == 1):            stickerNeed += oneDigit    return stickerNeed % MODnumber = int(input())result = sticker(number)print(result % MOD)

But it still cannot handle the really big numbers and gives time limit exceed. Can you help me out? What wrong with my code?