What does above exception points to in exception info thrown?

The simplest built-in exception as below:

>>> 1/0Traceback (most recent call last):  File "<stdin>", line 1, in <module>ZeroDivisionError: division by zero

Throw exception info ,then whole press is done.

Define function f1 and not to define myException:

def f1():    try:        print(1/0)    except:        raise myException('my exception')

Call f1():

>>> f1()Traceback (most recent call last):  File "<stdin>", line 3, in f1ZeroDivisionError: division by zeroDuring handling of the above exception, another exception occurred:Traceback (most recent call last):  File "<stdin>", line 1, in <module>  File "<stdin>", line 5, in f1NameError: name 'myException' is not defined

When the info

Traceback (most recent call last):  File "<stdin>", line 3, in f1ZeroDivisionError: division by zero

thrown out,exception of print(1/0) is handled as we have seen that in the beginning.
Why the statement in the middle line is During handling of the above exception, another exception occurred: ,instead of After handling of the above exception, another exception occurred:?
What is above exception in the statement During handling of the above exception?It points to try ... except structure in f1 ,instead of exception resulted by 1/0?
If above exception points to exception resulted by 1/0,then After handling of the above exception, another exception occurred is better to describe all the exceptions here!