First post, long time lurker, couldn't get the format the way I wanted it to be. -sorry
I'm trying to convert part of a binary file to a date/time (in Python). But whatever I try I'm unable to find the proper conversion.
My guess is that the left byte (0x30) is not part of the data, and the remaining 8 bytes contain the relevant data.
Below are the binary parts, both in decimal and in Hex, and the date/time they represent. Any help is highly appreciated.
48 101 26 235 227 242 150 197 6530 65 1a eb e3 f2 96 c5 41 -- should read as 16 December 2023 at 15:0348 198 54 133 112 138 151 197 6530 c6 36 85 70 8a 97 c5 41 -- should read as 17 December 2023 at 12:3748 74 38 27 107 41 116 196 6530 4a 26 1b 6b 29 74 c4 41 -- should read as 1 October 2022 at 12:49I've tried to unpack the data as either double or long long int and then obtain a date from it. I've searched the site and tried chat GPT to no avail.
Extra sample data
30 23 84 b1 a8 b5 97 c5 41 : 17 December 2023 at 18:4530 3f 91 e7 96 b5 97 c5 41 : 17 December 2023 at 18:45 (slightly later)30 a6 d6 2f d1 b5 97 c5 41 : 17 December 2023 at 18:4630 e8 16 9c b9 b5 97 c5 41 : 17 December 2023 at 18:47