HOW TO: Python: Countdown until matching digits?

So we have to complete a task where we enter a digit from 20-98 (inclusive). The task is to make it so that it stops counting down (or breaks) whenever there's a same-digit number (88,77,66,55,44,33,22). I am able to make it pass tests if I enter 93, but not for other numbers (for ex. 30).

If we enter a digit (for example 93), the output would be:

939291908988

is my code so far:

x = int(input())while 20 <= x <= 98:    print(x, end='\n')    x -= 1    if x < 88:        break    elif x < 77:        break    elif x < 66:        break    elif x < 55:        break    elif x < 44:        break    elif x < 33:        break    elif x < 22:        break    elif x < 11:        breakelse:    print("Input must be 20-98")

I was wondering how I need to change my code so that it can apply to all numbers, and so I do0n't have to write so many if-else statements for all the possible same-digit numbers.